вывод полного пути до excel-файла в exception
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@@ -4,9 +4,11 @@
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*/
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package ru.dmitriymx.astralcheckreport;
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import org.apache.logging.log4j.message.FormattedMessage;
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import org.apache.poi.openxml4j.exceptions.InvalidFormatException;
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import org.slf4j.Logger;
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import org.slf4j.LoggerFactory;
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import org.slf4j.helpers.MessageFormatter;
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import ru.dmitriymx.astralcheckreport.objects.*;
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import ru.dmitriymx.astralcheckreport.tarifs.*;
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@@ -30,7 +32,8 @@ public class Main implements Runnable {
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}
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private void start() {
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logger.info("Astral check report v1.0 alpha");
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logger.info("Astral check report v1.1 beta");
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logger.info("Developed by DmitriyMX <mail@dmitriymx.ru>, 2016");
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logger.trace("Init config");
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try {
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@@ -51,10 +54,12 @@ public class Main implements Runnable {
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}
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logger.trace("Load excel file");
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File excelFile = new File(properties.getProperty("file"));
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try {
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excel = new ExcelReader(new File(properties.getProperty("file")), "Операции");
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excel = new ExcelReader(excelFile, "Операции");
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} catch (IOException | InvalidFormatException e) {
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logger.error("Load excel file", e);
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logger.error(MessageFormatter.format(
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"Load excel file \"{}\"", excelFile.getAbsolutePath()).getMessage(), e);
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return;
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}
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